Physics, asked by snehajana42, 1 month ago

An athlete complete one round of a circular track of diameter 200m in 40sec. What will be the distance covered and displacement at the end of 2 min and 2 second​

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Answered by Anonymous
250

QuestioN:

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  • An athlete complete one round of a circular track of diameter 200m in 40sec. What will be the distance covered and displacement at the end of 2 min and 2 second.

{ }

{\frak{Clearly,\:we\:have}}

{ }

\:\:\:\:\:\curlyeqsucc{\sf{Diameter\:of\:Circular\:track\:=\:200m}}

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\:\:\:\:\:\:\:\:\:\curlyeqsucc{\sf{Radius\:(r)\:=\:{\dfrac{200}{2}}\:=\:100m}}

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\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\curlyeqsucc{\sf{Time\:taken\:by\:Athlete\:to\:complete\:one\:round\:=\:40\:sec}}

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\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━

{ }

Now,

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{\sf{\red{\bigstar{\:Speed\:=\:\dfrac{Distance}{Time}}}}}\:\\ \\ {\:\:\:\:\:\:\sf{\red{\bigstar{\:Circumference\:of\:Circle\:=\:2 \pi r}}}}

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  • 2 min 20 seconds = 140 seconds

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\:\:\:\:\:\:\:\gg\:{\sf{\dfrac{140}{40}}\:=\:3.5}

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\gg\:\small{\sf{Distance\:Covered\:=\:3.5\:\times\:Circumference}}

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\gg\:\small{\sf{Distance\:Covered\:=\:3.5\:\times\:2\:\times\:{\dfrac{22}{7}}\:\times\:100}}

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\gg\:\small{\sf{Distance\:Covered\:=\:5\:\times\:2\:\times\:22\:\times\:100}}

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\:\:\:\:\:\:\:\:\:\gg\:{\sf{Distance\:Covered\:=\:2200m}}

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Hence,

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\:\therefore\:{\underline{\sf{The\:distance\:covered\:at\:the\:end\:of\:2\:min\:20\:sec\:is\:{\textsf{\textbf{2200m}}}}}}.

And,

\:\therefore\:{\underline{\sf{Displacement\:is\:{\textsf{\textbf{200m}}}\:as\:it\:return\:to\:initial\:position\:again}}}.

\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━

{\blue{\sf{\bf{@ℐᴛᴢӇᴀᴘᴘʏҨᴜᴇᴇɴ࿐}}}}

Answered by lata40386
2

Answer:

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