Question

an athlete completes one round of a circular track of diameter 200m in 30 second .find the distance travelled by the athlete and the magnitude of displacement of the athlete at the end of 30 second.

Answer 1

Answer

Explanation:

diameter=200m

radius = d÷2

= 200÷2

= 100m

Let π = 3.14

Since d= S × T

Distance= 2πr= (Circumference of the circle)×(time)

= 2×3.14×100×15

= 628×15

= 9420m^2

Since, the starting & ending point is the same

Therefore, Displacement=0

So, distance travelled by the athlete is 9420 m^2 & displacement is 0

Answer 2

diameter=200m

radius = d÷2

= 200÷2

= 100m

Let π = 3.14

Since d= S × T

Distance= 2πr= (Circumference of the circle)×(time)

= 2×3.14×100×15

= 628×15

= 9420m^2

Since, the starting & ending point is the same

Therefore, Displacement=0

So, distance travelled by the athlete is 9420 m^2 & displacement is 0