Question

an athlete completes one round of a circular track of diameter 200m in 40 seconds what will be the distance covered and the displacement at the end of 2 minutes​

Answer 1

Explanation:

hey mate,

d = 200m

i.e, 2r = 200m

r = 100m

time required to complete 1 round = 40 sec

no. of rounds complete in 2 sec and 20 sec ( i.e. 140sec) = 140 / 40

= 3.5 sec

distance covered in 140 sec =

$2\pi \: r \times 3.5$

$= 2 \times \frac{22}{7} \times 100 \times 3.5$

=2200m

displacement = 0

for 3 complete rounds, the displacement = 0

At the end of his motion, the athlete will be in the diametrically opposite position. That is, displacement = diameter = 200 m.

Hence, the distance covered is 2200 m and the displacement is 200 m

hope this would help you!!

Answer 2

Answer:

Distance = 1884 m

Displacement = 0 m

Explanation:

GIVEN :-

Diameter of the circular track = 200 m

Radius of the circular track = 200 / 2 = 100 m

Distance covered = Circumference of circle = ‘2πr’ units

= 2*3.14*100 m

= 628 m

=> Hence, Distance travelled in 40 seconds = 628 m

Distance covered in two minutes = ?

=> Now, let’s find the distance covered in two minutes.............

Time taken to cover 628 m = 40 secs

Distance covered in 1 sec= 628 / 40

= 15.7 m

Time travelled = 2 mins = 120 secs

Distance covered in two minutes = 15.7 * 120

= 1884 m

Hence, Distance covered in two minutes is 1884 m

The displacement =0. (this is because the initial and final position of athlete is

same