An athlete completes one round of a circular track of diameter 200m in 40s. What will be the distance covered and the displacement at the end of 2 minutes 20 s?
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Answer:
total time = 2 minutes 20 seconds
=2×60+20
=140 seconds
in 40seconds, number of rounds completed =1/40×140
=3.5rounds
distance covered in one round = 2πr
=2×3.14×100
= 628m
distance covered in 3.5 rounds =628×3.5
total distance covered =2198m
for displacement at the end of 140seconds, athelete 's position will be B if he starts from A point. so shortest path is ab= 200m
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