Question

An athlete completes one round of a circular track of diameter 200m in 40second.what will be the distance covered and the displacement at the end of 2minutes 20second?

Answer 1

number of round in 2 min 20 sec
i.e. 140 sec
= 140/40 = 3.5

distance covered in one round = 2×π×r
                                                 =2×(22/7)×100
                                                 =4400/7 m

distance covered in 3.5 round = (4400/7)×3.5 = 2200 m
                                                =2.2 km

displacement = shortest distance = 2r = 200 m