If 6x = sec A and 6/x = tan A ,find the value of 9(x sq. - 1/xsq. )
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6x=secA
or, x=secA/6
or, x²=sec²A/36
and 6/x=tanA
or, 1/x=tanA/6
or, 1/x²=tan²A/36
9(x²-1/x²)=9(sec²A/36-tan²A/36)=9(sec²A-tan²A)/36=9/36=1/4;
(∵, sec²A-tan²A=1)
or, x=secA/6
or, x²=sec²A/36
and 6/x=tanA
or, 1/x=tanA/6
or, 1/x²=tan²A/36
9(x²-1/x²)=9(sec²A/36-tan²A/36)=9(sec²A-tan²A)/36=9/36=1/4;
(∵, sec²A-tan²A=1)
Answered by
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Hope it helps you!
Regards,
Shobana
^_^
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