Question

an athlete completes one round of a circular track of diameter 200 m in 40 seconds what will be the distance covered and the displacement at the end of 2 minutes and 20 seconds

Answer 1

HELLO

TOTAL TIME TAKEN= 2 MINS 20 SECONDS

= 2 ×60 +20 SEC

=140 SECS

NOW , IN 40 SECS NO OF ROUNDS MADE = 1

IN 140 SECS NO OF ROUND MADE = 1/40×140 = 3.5 ROUNDS

MAGNITUDE OF DISPLACEMENT AT THE END OF 2 MIN AND 20 SECOND WILL BE

AC WHOLE SQUARE = AB WHOLE SQUARE

+ BC WHOLE SQUARE

AC WHOLE SQUARE = 10 WHOLE SQUARE +10 WHOLE SQUARE

AC = √200 = 14.143 M ETRE

.........................................................................................@TRISHA:)