Question

the number of positive divisors of 1995 is?

Answer 1

We know that for an integer n = a^p*b^q*c^r, then the number of factors of n will be expressed by the formula = (p + 1)(q + 1)(r + 1).

That means here, we have to add 1 to each exponent and multiply the result.

Now,

(1) Write the prime factorization of 1995:

= > 3^1 * 5^1 * 7^1 * 19^1.

So, the number of positive divisors of 1995 = (1 + 1)(1 + 1)(1 + 1)(1 + 1) = 16.

Therefore, the number of positive divisors of 1995 is 16.

Hope this helps!

Answer 2

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