Physics, asked by bsingh76kvi, 8 hours ago

An athlete completes one round of a circular track of radius R in 20 s with constant speed. What will be his displacement at the end of 1 minute 10 second? ​

Answers

Answered by Rudranil420
21

Answer:

\qquad\qquad\underline{\textsf{\textbf{ \color{magenta}{AnSwEr}  }}}

Question :-

  • An athlete completes one round of a circular track of radius R in 20 s with constant speed. What will be his displacement at the end of 1 minute 10 second?

Find Out :-

  • What will be his displacement at the end of 1 minute 10 second?

Solution :-

Total time duration in consideration = 2 min 20s = 140 sec

He completed 1 round in 40 sec.

In 140 sec, he will cover,

→ 140/40

→ 3.5 rounds

After 3.5 rounds, he would be on the opposite side of the starting point.

So, the displacement will be the diameter or 2R.

Answered by PoojaBurra
46

Given: An athlete completes one round of a circular track of radius R in 20 s with constant speed.

To find: His displacement at the end of 1 minute 10 seconds.

Solution:

  • When we convert 1 minute 10 seconds into seconds it is equal to 70 s.

        (1 * 60) + 10 = 70 s

  • If the athlete completes one round in 20 seconds, then he completes three rounds in 60 seconds or one minute.

        \frac{60}{20}  = 3

  • After completing 3 rounds, his displacement is zero because he is back to his initial position.
  • If he completes one round of the circular track in 20 s, in the 10 seconds left out of 70, he travels half the circular track.

        \frac{R * 10}{20} = 2R

  • Since the diameter of a circle is twice the radius (R) of the circle, his displacement from his initial position is equal to the diameter of the circular track.

Therefore, his displacement at the end of 1 minute 10 seconds is 2R.

Similar questions