Question

An athlete consumes 4000 kilocalories per day through his diet. His power in watt is

Answer 1

1 calorie =4.2 J

4000 k cal=4000×10^3×4.2=168×10^5 J

1 day =24×60×60=86400 s

power= energy /time

=16800000/86400=194.44 watt

Answer 2

Answer:

The power of the athlete is 194.44 watt.

Explanation:

Given that,

Energy = 4000 kilo calories

We know that,

1 calorie = 4.2 J

So,

Energy $E =4000\times10^{3}\times4.2$

$E = 16800000\ J$

For time,

1 day = 24 hours

$t=1\ h=24\times60\times60\ s$

$t=86400\ s$

We need to calculate the power in watt

The power is the amount of energy per unit time.

$P = \dfrac{E}{t}$

$P = \dfrac{16800000}{86400}$

$P=194.44\ watt$

Hence, The power of the athlete is 194.44 watt.