An athlete jumps at an angle of 30⁰ with a maximum speed of 9.8 m/s²
a) obtain an expression to calculate the horizontal range is covered by the athlete
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Answer:
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Explanation:
The equation of motion says:
v=u+at
Considering only the vertical component of his jump we can get the time it takes to reach his maximum height from:
0=uy−gt
usinθ=uy which is the vertical component of his initial velocity u.
∴0=usinθ−gt
∴t=usinθg
Since θ=23 this becomes:
t=4sin239.8=0.159s
The 2nd part of his journey as he falls to earth is a mirror image of the first part so:
t=2×0.159=0.32s
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