Question

An athlete runs along a circular track of radius of 100m and he completed 2 1/2 round,find the distance and displacement.​

Answer 1

Given:-

• Radius of circular track = 100m.
• Number of round taken by athlete = 2 ½ rounds.

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To Find:-

• Distance covered by athlete
• Displacement covered by athlete

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Theory\Formula Used:-

• Distance is the total length covered by body from initial point to final point.
• Displacement is the shortest distance between final point and initial point.
• Diameter = 2 × Radius
• Circumference of circle = 2 π r

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Solution:-

➥ Circumference of the circular track

= 2 π r

= 2 × 3.14 × 100

= 618m

➥ Distance covered by athlete

= 2½ × 618

= 2.5 × 618

= 1545m

➥ Displacement

= shortest distance

= Diameter

= 2 × Radius

= 2 × 100

= 200m

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Answer:-

▪︎Distance covered by athlete is 618m.

▪︎Displacement covered by athlete is 200m.

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Answer 2

Answer:

So 3/4 of 360° is 270°

So distance is

270/360 * 2(pi)100

150(3.14)=471meters

Now the displacement is the shortest distance from the initial point to the final point. So we have to find the chord which joins these two point(for more better understanding try to cut the circle into 4 different quarters). So by applying pythoagoreas theorem we get

Diplacement=((500)^2+(500)^2)^1/2

=(5000)^1/2

=50(2)^1/2 or 50(root)2meters

Hence these are your answers hope this helps you :)