Question

an athlete runs at 8meter per second for 4 second,6meter per second for 3 seconds and then 10meter per second for 2seconds.his average speed is

Answer 1

Answer:

Displacement during first journey S

1

=3×4×60=720 m

Displacement during second journey S

2

=4×3×60=720 m

Total displacement S=S

1

+S

2

=1440 m

Total time t=(4+3)×60=420 s

Average velocity V

avg

=

t

S

=

420

1440

=3.42 m/s