An atificial satelite move in a circular orbit of radius 42250 km what will be its speed if it takes 24hours to complete revolution
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Answered by
2
Radius=42250km
Time=24 hours
Then circumference=2*22/7*42250=1859000/7 km
Then
Velocity= circumference /time=1859000/7*1/24 =232375/21=11065.47 km/h=3073.7417m/s =3.07km/s
Time=24 hours
Then circumference=2*22/7*42250=1859000/7 km
Then
Velocity= circumference /time=1859000/7*1/24 =232375/21=11065.47 km/h=3073.7417m/s =3.07km/s
Answered by
3
Hey there!
Given,
Radius (r) = 42250 km
Time (t) = 24 hours
Distance will equal to perimeter of the orbit
= 2πr
= 2π * 42250
Speed of artificial satelite
= 2π * 42250/24
= 11059 km/h
Hope It Helps You!
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