Question

an atom has a electronic in the first (k) shell(L) shell and 2 eletrons in the third (M) shell Give its Electronic configuration and find principal quantam no and total no of sub shells and total no of s-orbitals and p - electrons
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Answer 1

Heyyy!!Your answer--

Total no. of electron-2(K)+8(L)+2(M)=12 electron

• Electronic configuration

$1s {}^{2} \: 2s {}^{2} \: 2p {}^{6} \: 3s {}^{2}$

Principal Quantum no. -- n= 3

Total no. of subshell (l= n-1)

= 0+1+1+2=4

Number of orbital is given by principal Quantum number .So,no of s orbital= 2+3=5

Total no. of p-electron = 6 (No. of electron in p orbit)