Question

an atom of an element has fourth shell as the valence shell. thr difference between electrons present in l- and m-,k-,and n- shells are 1 and 0, respectively. find the atomic number of an element

Answer 1

Answer:

The correct answer would be Scandium [ atomic no.  21 ].

Explanation:

On doing the electronic configuration of scandium the K,L,M,N shells would be having electrons like 2,8,9,2 respectively.

So, the difference of L and M shells would be 9-8 i.e 1 . Similarly , K and N shells would be 2-2 i.e 0.

So , we can conclude that the appropriate answer satisfying the given question would be Scandium [21].

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