Question

An atom of element x weighs 6.64 × 10^-23 . Calculate the no. of moles in 40000 gm of it.

Answer 1

ASSALAMUALAIKUM

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weight of 1 atom = 6.64×10^-23 g

so, no. of atoms in 40000 kg

= 40000×10^3 / 6.64×10^-23

= 265,600× 10^26 atoms

As, 1 gram atom = no. atoms in one mole = 6.02×10^23 (avagadro number)

so, no. of gram atom

= 265,600×10^26/6.02×10^23
= 1598gram atoms

INSHAALLAH it will help you!

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Answer 2

heya..!!!

Answer:

weight of 1 atom = 6.64×10^-23 g

so, no. of atoms in 40000 kg 

= 40000×10^3 / 6.64×10^-23

= 265,600× 10^26 atoms

As, 1 gram atom = no. atoms in one mole = 6.02×10^23 (avagadro number) 

so, no. of gram atom

= 265,600×10^26/6.02×10^23
= 1598gram atoms