Question

An atom of some element Y weighs 6.644 × 10-23 g. Calculate the number of gram-atoms in 40 kg of it.?????

Answer 1

Mass of 1 mole Y atoms= mass of 1 atom × Avogadro constant

= 6.644 × 10-23 × 6.022×1023

= 40 g

So, the atomic mass of Y = 40

No. of gram-atoms (or moles) of Y

$\implies \frac{mass \: of \: y}{atomic \: mass}$

$\implies 40 × 1000/40$

$\implies 1000.$

Answer 2

${ \red{\mathfrak{\huge{A}}}}{\underline {\underline{\mathfrak{\huge{nswer}}}}}$




Mass of 1 mole Y atoms= mass of 1 atom × Avogadro constant

➾ 6.644 × 10-23 × 6.022×1023
➾ 40 g

♦ The atomic mass of Y = 40

No. of gram-atoms of Y = 1000

$\huge \implies \huge \bf\frac{Mass \: of \: Y }{Atomic Mass }$

$\huge \implies \bf \frac{40 \times 1000}{40}$

$\huge \implies {40}$