Question

In group of four two have same sun sign.If we select two randomly than what is the probability that two have same sun sign

Answer 1

Answer:

S = {sun sign1,sun sign2,sun sign3,sun sign4}

n (s)= 4

Let A be the event that the selected sun sign is same

A= { sun sign1 sun sign2,sun sign1 sun sign3, sun sign1 sun sign4,sun sign2 sun sign3,sun sign2 sun sign4,sun sign3 sun sign4}

n (A)= 6

P (A) = n (A)/n (S)

= 6/4

= 3/2

Hope this will help u

Not much sure but it is correct