Question

An atomic orbital has n = 3. What are the possible values of I and m₁?

Answer 1

Answer:

Possible values for n = 0, 1, 2 and m= -1/2, +1/2

Answer 2

Answer:

l = 0, 1, 2

m₀ = 0

m₁ = – 1, 0, 1

m₂ = – 2, – 1, 0, 1, 2

Explanation:

As per the question given data

n = 3

As we know,

In an atomic orbital

n = First quantum number

l =  Angular quantum number

m = Magnetic quantum number

For a given value of n, Angular quantum number (l) can have values from 0 to (n – 1).

∴ For n = 3

l = 0, 1, 2

For a given value of l, magnetic quantum number (m ) can have values from -l to +l

Therefore,

For l = 0, m = 0

l = 1, m = – 1, 0, 1

l = 2, m = – 2, – 1, 0, 1, 2

Hence, for n = 3

l = 0, 1, 2

m₀ = 0

m₁ = – 1, 0, 1

m₂ = – 2, – 1, 0, 1, 2