Question

an auditorium is 46 m long and 3m broad .the area of its door and window is 50 sq meter .find the height of the auditorium if the cost of preparing the wall is 5000 at 9 per square meter.

Answer 1

I think the height of the auditorium may be the 305/49 metre .

Answer 2

Height of auditorium is 2.85 m.

Step-by-step explanation:

Since we have given that

Area of door and window = 50 sq. m

Length of auditorium = 46 m

Width of auditorium = 3 m

Let the height of auditorium be 'h'.

Total cost= Rs. 5000

Cost per square meter = Rs. 9

So, Total area of wall = $\dfrac{5000}{9}=505.55$

Surface area of auditorium would be

$2(lb+bh+lh)=2(46\times 3+3\times h+46\times h)=2(138+3h+46h)=2(138+49h)$

So, it becomes,

$2(138+49h)-50=505.55\\\\2\times 138+49\times 2h=505.55+50\\\\276+98h=555.55\\\\98h=555.55-276\\\\98h=279.55\\\\h=\dfrac{279.55}{98}\\\\h=2.85$

Hence, height of auditorium is 2.85 m.

# learn more:

An auditorium is 46 m long and 3m broad the area of its door and window is 50sq meter find the height of the auditorium if the cost of preparing the wall is 5000 at 9per square meter.

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