Math, asked by sunilchoudary, 1 year ago

an auditorium is 46 m long and 3m broad the area of its door and window is 50sq meter find the height of the auditorium if the cost of preparing the wall is 5000 at 9per square meter.

Answers

Answered by ehesan
2
500000000000000000000
Answered by pinquancaro
4

The height is 2.85 meter.

Step-by-step explanation:

Given : An auditorium is 46 m long and 3 m broad the area of its door and window is 50 sq meter.

To find : The height of the auditorium if the cost of preparing the wall is 5000 at 9 per square meter?

Solution :

Total cost = Area × Rate

The wall is 5000 at 9 per square meter.

i.e. 5000=\text{Area}\times 9

\text{Area}=\frac{5000}{9}

An auditorium is 46 m long and 3 m broad.

Let the height be h.

The area of the window is given by,

A=2(lb+bh+hl)

\frac{5000}{9}=2(46\times 3+3\times h+h\times 46)

\frac{5000}{9}=2(138+3h+46h)

\frac{5000}{9}=276+98h

\frac{5000}{9}-276=98h

98h=\frac{5000-2484}{9}

98h=\frac{2516}{9}

h=\frac{2516}{9\times 98}

h=2.85

Therefore, the height is 2.85 meter.

#Learn more

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