An automobile accelerates from 54 km/h to 90 km/h with a constant acceleration of 2.52 km/h. How far does it travel during this time?
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Answer:
going by the formulae
(v2-u2)/2a=s
therefore, (90*90-54*54)/(2*2.52)=s
s=1226.98 km
therefore distance travelled is 1226.98 km
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