the sum of 5 terms of an A.P. is same as the sum of its 11 terms then sum of 16 terms is
Answers
Answered by
3
Answer:
Step-by-step explanation:
Sum of 5 terms of an AP = 5/2×[2a+4d]
=5(a+2d)
=5a+10d
Sum of 10 terms of an AP=10/2×(2a+9d)
=10a+45d
Sum of 16 terms of AP =16/2×(2a+15d)
=16a+120d
Now,according to the question,
5a+10d=10a+45d
5a=-35d
a = -7d.
So,S16=16(-7d)+120d
=-112d+120d
=8d
From value of d it can be calculated.
Answered by
1
Answer:
8d
Step-by-step explanation:
this the answer to this question
Similar questions