An automobile engine develops 100 H.P. when rotating at a speed of 1800 rad per min. The torque it delivers is
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Answered by
10
100 HP = 74570 W or 74.57 KW
Now,
P = 2*π*N*T/60
where, P is the power (in W), N is the operating speed of the engine (in r.p.m.) and T is the Torque (in N.m).
Therefore,
74570 = 2*π*1800*T/60
i.e. T = 395.606 N.m
Now,
P = 2*π*N*T/60
where, P is the power (in W), N is the operating speed of the engine (in r.p.m.) and T is the Torque (in N.m).
Therefore,
74570 = 2*π*1800*T/60
i.e. T = 395.606 N.m
Answered by
1
Answer:
Explanation:
Acceleration = (Final velocity - Initial velocity )/ Time
Acceleration = (0 - 50) / 5
Acceleration = -50 / 5
Acceleration = -10m/s^2
Hope this answer is correct..........
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