Question

An automobile moving at a speed of 72 km/h is brought to rest in 2 seconds by application of brakes. How much distance does the automobile covers in these 2 seconds ?

Answer 1

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Answer 2

Answer:

s = 20 meters

Explanation:

Given that,

Initial speed of the automobile, u = 72 km/h = 20 m/s

It comes to rest, v = 0

Time taken, t = 2 s

Let a is the acceleration of the automobile. Using the first equation of kinematics as :

$a=\dfrac{v-u}{t}$

$a=\dfrac{-20}{2}$

$a=-10\ m/s^2$

Let s is the distance covered by the automobile in 2 seconds. Using third equation of kinematics as :

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{-(20)^2}{-2\times 10}$

s = 20 meters

So, the distance covered by the automobile is 20 meters. Hence, this is the required solution.