An automobile starts from rest and attains a velocity 72 km per hour in 10 second find the distance and acceleration if it is uniform
Answers
Answered by
1
acceleration =72/10=7.2m/s distance=5/18×72=20m/s×10s=200m
Answered by
1
Hey dear here is your answer!!!!
According to question :-
u = 0
v = 20 m / s
t = 10 seconds
a = ?
_______
Using first equation of motion ;
v = u + at
20 = 0 + 10a
a = 2 m / s^2
_________
Using third equation of motion
v^2 - u^2 = 2as
400/4 = s
100 m = s
Distance is 100 m
Acceleration is 2m / s^2
__________
Hope it helps u dear....☺️☺️☺️
According to question :-
u = 0
v = 20 m / s
t = 10 seconds
a = ?
_______
Using first equation of motion ;
v = u + at
20 = 0 + 10a
a = 2 m / s^2
_________
Using third equation of motion
v^2 - u^2 = 2as
400/4 = s
100 m = s
Distance is 100 m
Acceleration is 2m / s^2
__________
Hope it helps u dear....☺️☺️☺️
Similar questions