Question

An automobile tire is pumped up to a gauge pressure of 2.0 x 10° Pa when the temperature is 27. C. What is its gauge pressure after the car has been running on a hot day so that the tire temperature is 77 C? Assume that the volume remains fixed and take atmospheric pressure

Answer 1

Answer:

Explanation:

Since volume is fixed, P/T is constant

Assuming initial pressure that you have mentioned in your question is 2 x 10^5 Pa,

2x10^5/300=p/350

2.3x10^5 Pa

Hope this answer helped you

Answer 2

Answer:

The gauge pressure is $2.3*10^{5} Pa$.

Explanation:

It is given that gauge pressure is $2*10^{5} Pa$

One of the temperature is $27^{0} C=300K$

Second temperature $77^{0} C=350K$

It is given that volume is fixed,

$\frac{P}{T}$ is constant

$\frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }$

Using the given values

$\frac{2*10^{5} }{300 } =\frac{P_{2} }{350 }$

Solving we get

$P=2.3*10^{5} Pa$

The required pressure is $2.3*10^{5} Pa$

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