an automobile traveling with speed of 60km/hr can brake to stop within a distance of20 m . if the car is going twice at fast that is 120km/hr . what will be the stopping distance nu
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Ist Case :
0=( 50/3 ) ^2 −2a×20.....(i)
IInd Case :
0=( 100/3)^2 −2ax.....(ii)
From (i) and (ii)
x=80 m.
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