In each of the following, one of the six trigonometric ratios is given. Find the values of the other trigonometric ratios.
(i) sinA = 2/3 (ii) cos A =4/5
(iii) tan θ = 11 (iv) sinθ = 11/15
(v) tan α =5/12 (vi) sinθ =√3 /2
(vii) cosθ = 7/25 (viii) tan θ = 8/15
(ix) cosθ = 12/5 (x) sec θ = 13/5
(xi) cosecθ =√10 (xii) cosθ = 12/15
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Step-by-step explanation:
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Trigonometric ratios
Step-by-step explanation:
(i) Given (i) sinA = 2/3
sin A = 2/3 = opposite side / hypotenuse
So adjacent side = √(3² - 2²) = √(9-4) = √5
The other trigonometri values are:
Cos A = Adjacent / hypotenuse = √5/3
Tan A = Sin A/ CosA = 2/3 / √5/3 = 2 /√5
Cosec A = 1/ SinA = 3/2
Sec A = 1/ Cos A = 3/√5
Cot A = 1/Tan A = √5 / 2
(ii) cos A = 4/5
Cos A = 4/5 = Adjacent / hypotenuse
So opposite side = √(5² - 4²) = √(25-16) = √9 = 3
The other trigonometri values are:
Sin A = opposite / hypotenuse = 3/5
Tan A = Sin A/ CosA = 3/5 / 4/5 = 3/4
Cosec A = 1/ SinA = 5/3
Sec A = 1/ Cos A = 5/4
Cot A = 1/Tan A = 4/3
Solve the rest of the question in the same method.
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