In an isosceles triangle ABC, if AB = AC = 25 cm and BC = 14 cm, then the measure of altitude from A on BC is
A. 20 cm
B. 22 cm
C. 18 cm
D. 24 cm
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Answer:
In triangle ABC
Let tge altitude be AD on BC
AC=25cm
AB=25cm
BC=14cm
Therefore DC= 1/2*BC
=1/2*14
=7
By Pythagoras theorem,
AD^2+CD^2=AC^2
AD^2+7^2=25^2
AD^2+49=625
AD^2=625-49
AD^2=576
AD=24
Therefore altitude from A on BC is 24 cm
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