Question

An automobile travelling at 48km/h can be stopped in a maximum distance if 40m by applying the brakers. If the same autombile is travelling at 96 km/h, what is the maximum stopping distance

Answer 1

$v = 48 \times 5 \div 18 = 13.33ms ^{ - 1} \\ a = 40 \div 13.33 = - 3ms {}^{ - 2} \\ v = 96 \times 5 \div 18 = 26.66 \\ \\ - 3 = x \div 26.66 = 26.66 \times 3 = x \\ x = 80$