An automobile travelling at 80 km hr−1 has tyres of radius 80 cm. On applying brakes, the car is brought to a stop in 30 complete turns of the tyres. What is the magnitude of the angular acceleration of the wheels? How far does the car move while the brakes are applied
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Distance traveled after applying brakes is given as 30 complete revolutions.
Distance = circumference x 30 = 2x3.14x0.8x30 = 150.72m
v^2= u^2 - 2as
u^2= 2as
a= u^2/2s
a= 22.2^2/(2x150.72)
a= 1.63 m/s^2 is the deceleration.
80kmph is 22.2 mps
linear acc = angular acc x radius
angular acc = 1.63/0.8 = 2.0375 rad/s^2
Distance = circumference x 30 = 2x3.14x0.8x30 = 150.72m
v^2= u^2 - 2as
u^2= 2as
a= u^2/2s
a= 22.2^2/(2x150.72)
a= 1.63 m/s^2 is the deceleration.
80kmph is 22.2 mps
linear acc = angular acc x radius
angular acc = 1.63/0.8 = 2.0375 rad/s^2
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