An automobile vehicle has a mass of 100kg.What must be the force between vehicle and road if the vehicle is to be stopped 10m. The initial velocity of vehicle is 100m/s.
Answers
Given
- Initial Velocity = 100 m/s
- Distance = 10 m
- Final Velocity = 0 m/s
- Mass = 100 kg
To Find
- The Force applied
Solution
● The force applied can be found using Newton's second law. But before that we have to use the third law of motion (v²-u² = 2as) to find the acceleration of the body. Then simple substitution would give us our answer
✭ Acceleration of the vehicle :
→ v²-u² = 2as
→ 0²-100² = 2 × a × 10
→ -10000 = 20a
→ -10000/20 = a
→ Acceleration = -500 m/s²
- Now we shall substitute these values in the formula, F = ma
✭ Force Applied
→ F = ma
→ F = 100 × (-500)
→ F = -50000 N
- Ignoring Negative Sign [The force is in negative because it is against the motion]
→ F = 50000 N
Answer:
Question:-
An automobile vehicle has a mass of 100kg.What must be the force between vehicle and road if the vehicle is to be stopped 10m. The initial velocity of vehicle is 100m/s
Given:-
- Initial velocity given : 100 m/s
- Distance given : 10 m
- Final velocity given: 0 m/s
- Mass given: 100 kg
To find out in the question:-
- The force applied on the object
Explanation:
Let's find out:-
☆Acceralarion of vehicle let's find by newton's third law
(V²- U² = 2 as)
Now Putting the value let find out
=》 0² - 100 ² = 2 × a × 10
=》 - 10,000 = 20 a
=》 - 10,000 ÷ 20 = a
=》- 5000 m/s
•°• Hence, Acceralarion of that vehicle becomes - 5000 m/s
NOW SUBSTITUTING THEIR VALUES
Formula used on
F= Ma
That is
F= M×A = ma
and,
- F = Force
- M = Mass
- A = Acceralarion
Now let's find out their substituting values
=》F= MA
=》 F = 100 × (- 500)
=》 F = - 50,000 Newton
•°• So , answer becomes 50,000 newton and as this is a kind of motion so it's value can't be negative
Knowledge required:-
- 1 kgf = 9.8 newton . ( kgf full form kilogram force)
- (-) × (-) = (+)
(+) × (+) = (+)
(+) × (-) = (-)
(-) × (+) = (-)
These above are the basic knowledge