An average force of 1200 newton acts on a 0.5 kg steel ball during a collision lasting 25 m seconds if the force is in the direction opposite of the initial velocity of 14 m per second then the final speed of the steel ball will be
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F = force applied = - 1200 N
v₁ = initial velocity = 14 m/s
v₂ = final velocity = ?
m = mass = 0.5 kg
t = time duration = 25 ms = 0.025 sec
using impulse-change in momentum equation
F t = m (v₂ - v₁ )
- 1200 (0.025) = (0.5) (v₂ - 14)
v₂ = - 46 m/s
hence the final speed is 46 m/s in same direction as the force
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