Question

an
concave mirror of focal length 1.5 m forms an image of an
object placed at a distance of 40 cm.
Find the position and nature of the image.
​

Answer 1

Answer:

the nature is crackle and it is in the position of  50cm

Answer 2

Answer:

Explanation:

Solution: F= -1.5 m=-150cm

object distance i.e u=-40cm

according to mirror formula,

1/F = 1/V + 1/U

-1/150 = 1/V -1/40

1/V= -1/50+1/40

1/V= -4/200+5/200

1/V=1/200

V=200cm

position between c and F

nature: Real and inverted