Question

an earthworm of length 15 cm is crawling along at 2 cm/s.An ant overtakes the worm in 5 seconds.How fast is the ant walking.

Answer 1

Answer:

I am assuming the speed of the earthworm is 2 cm per second

The ant is at the same position as the tail of the earthworm when the clock starts.

Let x be the speed of the ant.

In 5 seconds, the tail of the earthworm is 10 cm from the starting position.

Therefore the ant travels 10 cm + 15 cm = 25 cm in 5 seconds.

So the speed of the ant is 25 cm/5 sec = 5 cm per second.

Step-by-step explanation

Time in seconds Head of the earthworm. Ant

0. 15. 0

.

1 17. 5

2. 19. 10

3. 21. 18

4. 23. 20

5. 25 25

So speed of the ant is 5 cm per second

Hope it helps you