Question

An ebonite rod acquires a negative charge of 3.2×10^-10C. The number of excess electrons it has is given by
a)2×10^9
b)2×10^-9
c)2×10^-29
d)2×10^29

Answer 1

Heya!!

n= q/e= -3.2×10^-10/-1.6×10^-19= 2×10^9

So, (A)2×10^9 is the correct answer

Hope it helps✌️✌️