Chemistry, asked by abishnoi856, 11 months ago

An echo returned in 3 s. What is
the distance of the reflecting
surface from the source, given
that the speed of sound is
342 m s-l?​

Answers

Answered by karanjotgaidu
6

Answer:

Formula, 2d = v×t

v = 342 m/s

t = 3

2d = 342 × 3

d = 342 × 3/2

d = 513 m

The distance of the reflecting surface is 513 m

Hope it helps.......

Answered by Remi14
0

Speed of sound, v = 342 m s−1

Echo returns in time, t = 3 s

Distance travelled by sound = v × t = 342 × 3 = 1026 m

In the given time interval, sound has to travel a distance that is twice the distance of the reflecting surface and the source.

Hence, the distance of the reflecting surface from the source = (1026/2)m= 513m

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