Physics, asked by avijit26081997, 1 month ago

An edge-emitting LED operating at a wavelength of 1.3 μm launches −22 dBm of optical 

power into a single-mode fiber pigtail. The pigtail is connected to a singlemode fiber link 

which exhibits an attenuation of 0.4 dB km−1

at this wavelength. In addition, the splice losses 

on the link provide an average loss of 0.05 dB km−1. The transmission rate of the system is 

280 Mbit s−1

so that the sensitivity of the p–i–n photodiode receiver is −35 dBm. Penalties on 

the link require an allowance of 1.5 dB and a safety margin of 6 dB is also specified. If the 

connector losses at the LED transmitter and p–i–n photodiode receiver are each 1 dB, 

calculate the un-repeatered distance over which the link will operate.​

Answers

Answered by Sameenazir
0

Answer:

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Answered by mad210201
2

Given:

An edge-emitting LED

wavelength λ=1.3 μm

Power at the transmitter P_{i}=-22\ dBm

cabled fiber loss \alpha _{fc}=0.4

Splice loss \alpha _{j}=0.05\ dBkm^{-1}

Sensitivity P_{o}=-35\ dBm

allowance, D_{L}=1.5\ dB

Required safety margin, M_{a}=6\ dB

The system operated at 280\ mbit\ s^{-1}

To Find:  

The un-repeated distance over which the link will operate

Solution:

Use optical power budget equation

P_{i}-P_{o}=(\alpha _{fc}+\alpha _{j})L+\alpha _{cr}+D_{L}+M_{a}\\-22-(-35)=(0.4+0.05)L+2+1.5+6\\13=0.45L+9.5\\3.5=0.45L\\L=\dfrac{3.5}{0.45}\\L=7.8\ km

The un-repeated distance above the link will operate is 7.8 km.

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