Question

An edge of a variable cube is increasing at the
rate of 10 cm/sec. How fast the volume of the
cube will increase when the edge is 5 cm long.

Answer 1

Answer:

750cm^3/second

Step-by-step explanation:

given that

d(e)/dt=10cm/sec

we know that

v=e^3

differentiating on both sides

d(v)/dt=3e^2*d(e)/dt          (by applying chain rule)

we need to find the volume when e= 5cm

so ,

d(v)/dt=3*5^2 * de/dt

d(v)/dt=75*10

d(v)/dt=750 cm^3/sec