Question

an elastic spring of spring constant k is compressed by an amount x. show that it's potential energy is 1/2kx^2. Prove that it is conservative.
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Answer 1

Answer:

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Explanation:

F= kx  

Now as we know  

f.ds = potential energy  

differentiate

 potential energy = kx .ds  

k is a constant ........ and diff of x .ds is = x² / 2  

so here potential energy will be = 1/2 k x²