An elastic string of natural length l and force constant k is stretched by amount x. It is furthur stretched by length y
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Answer:
Potential energy stored, when it is extended by x, is
U1= (1/2) k *x²
Potential energy stored, when it is further extended by y, is
U2 = (1/2) k* (x+y)²
Work done = U2 - U1
= (1/2) k [x² +y² + 2xy - x²]
= (1/2) k*y ( 2x +y)
Explanation:
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