Physics, asked by yrajnish20812, 1 year ago

An elastic string of natural length l and force constant k is stretched by amount x. It is furthur stretched by length y

Answers

Answered by prashantro0
7

Answer:

Potential energy stored, when it is extended by x, is

U1= (1/2) k *x²

Potential energy stored, when it is further extended by y, is

U2 = (1/2) k* (x+y)²

Work done = U2 - U1

= (1/2) k [x² +y² + 2xy - x²]

= (1/2) k*y ( 2x +y)

Explanation:

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