Question

An elavator descends into a mine shaft at the rate of 6 metres per minute.if the descents starts from 10 metres above the ground level,how long will it take to reach -350metres

Answer 1

Considering the elevator to be at constant speed and the destination to be 350 m below ground level,

The elevator has to travel 10m till the ground, then 350 m more.

So, the total distance to travel is 360 m

If the elevator's speed is 6 metres/minute,
Then

Time= Distance/Speed
        = 360/6
        =60 minutes
        =1 hour

Thus the elevator would take 1 hour to reach its destination.


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Answer 2

distance=350-10=340m
time=340/6=56.67(paya)m