Question

calculate the work done in expanding 2moles of an ideal gas from 2 litre to 5 litre at 273 degree celcius

Answer 1

Answer:

The work done is $-4077.1J$.

Explanation:

Given: $2$ mole of an ideal gas from $2 ltr$ to $5 ltr$ at $273$ degree celcius.

Find : The work done .

Solution: Amount of work done in reversible is other mole expansion.

$w=-2.303n RT log \frac{V_2}{V_1}$

given, $n=2, R=8.314JK^{-1} mol^{-1}, T=273,V_{2} =5ltr, V_{1}= 2ltr.$

substituting the value in about equation.

$w=-2.303\times2\times8.314\times273\times log\frac{5}{2}$

$w=-2.303\times2\times8.314\times273\times0.39$

$w=-4077.1J$

Hence, the work done is $-4077.1J$.

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