Question

an electon is accelerated through a potential difference of 10,000v its de Broglie wavelength is nearly: me=9×10-31kg​

Answer 1

apply formula root2mev

Answer 2

Explanation:

It is given that :

An electron is accelerated through a potential difference of 10,000 V.

The relationship between the wavelength and the potential difference is given by:

$\lambda=\dfrac{h}{\sqrt{2meV}}$

Where

h is the Planck's constant

e is the charge on electron

m is the mass of electron

V is the potential difference

So, $\lambda=\dfrac{12.28}{\sqrt{V}}\times 10^{-10}\ m$

$\lambda=\dfrac{12.28}{\sqrt{10000}}\times 10^{-10}\ m$

$\lambda=12.28\times 10^{-12}\ m$

Hence, this is the required solution for de broglie wavelength.