Question

An electric bulb draws a current of 0.25 A when connected to a 240 V mains.

Its resistance is

(a) 960  (b) 96  (c) 100  (d) 60 ..​

Answer 1

Answer:

chhe fffjjfjfjfjfhdud

Answer 2

$\sf{\to{\boxed{R=96Ω}}}$

Explanation:

★Here:

$\sf{Given}\begin{cases}\sf{I=0.25A}\\ \sf{V=240v}\\ \sf{R=?}\end{cases}$

Using,,

$\mathtt{\boxed{\blue{</strong><strong>R</strong><strong>=</strong><strong>\</strong><strong>f</strong><strong>r</strong><strong>a</strong><strong>c</strong><strong>{</strong><strong>V</strong><strong>}</strong><strong>{</strong><strong>I</strong><strong>}</strong><strong>}}}$

We get,,

$\sf{R=\frac{240}{0.25}}$

$\sf{\implies{R=\frac{2400}{25}}}$

$\sf{\implies{R=\frac{2400}{25}}}$

$\sf{\implies{R=96Ω}}$

$\rule{200}2$

Hope it helps ❣️❣️