Question

An electric bulb draws a current of 0.8A from the source. The number of electrons passing per minute through the bulb will be

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Answer 1

Answer: 3 x $10^{20}$

Explanation:

I = ne/t

where, n = number of electrons and e = 1.6×10−19 C

I = 0.8 A , t = 60 seconds

Putting in formula,

0.8 = ( n x 1.6×10−19 )/ 60

48 = n x 1.6×10−19

n = 48 / 1.6×10−19

n = $30*10^{19}$ = 3 x $10^{20}$

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