Geography, asked by ooOOooTanyaooOOoo, 1 day ago

An electric bulb draws a current of .8 A and works on 250 V on the average 8 hours a day. a. Find the power consumed by the bulb b. If the electric distribution company changes Rs 5 for 6 KWH, what is the monthly bill for 60 days​

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Answered by deevapiprakash
0

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An electric bulb draws s current of B.A and works on 250 V on the average 8 hours a day.

Find the power consumed by the bulb

if the electric distribution company charges Rs 5 for 6 KWH, what is the monthly bill for 60 days.

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Solution

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Hint:Use the formula of Power, P = VI

Step 1: Note the given values

Potential difference, V=250V

Current, I =8A

Step 2: Finding the power consumed by Bulb

Power, P= VI

Putting the values in formula:

P=250×8

P=2000watts

Bulb works on the average of 8 hours a day.

So, Power consumed in one day:

P=2000×8

P=16000Wh = 16000kWh

Hence, Power Consumed in one day is 16kWh

Step 2: Finding the monthly bill electricity.

We know that:

Power Consumed in one day is 16kWh

Power Consumed in 60 days = 60×16 kWh = 960kWh

As given,

Bill for 6kWh = Rs. 5

So, Bill for 960kWh =

6

5

×960

=

6

5

×960

= Rs. 800.

So, Bill for 1 month =

2

800

= Rs. 400

Hence, monthly bill for electricity is Rs. 400.

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