An electric bulb has apower of 500 W. Express it in CGS units.
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Answered by
162
Hi_____________
we know dimension formula
o________________________
Power=Work/time=Energy /time
Dimension [P]= [ML^2T^-3]
n2 = n1 [M1/M2]^x [L1/L2]^2 [T1/T2]^-3
_______________________________
now convert SI unit into CgS unit
500w=500J/s
n2 = 500 [kg/g] [1m/cm]^2[1s/1s]^-3
=5*10^2*10^3 g*(10^2)^2 *(1s)^-3
=5*10^2*10^3*10^4 g cm^2 /s^3 =
5*10^9 g cm^2 /s^3.
hope it help.
we know dimension formula
o________________________
Power=Work/time=Energy /time
Dimension [P]= [ML^2T^-3]
n2 = n1 [M1/M2]^x [L1/L2]^2 [T1/T2]^-3
_______________________________
now convert SI unit into CgS unit
500w=500J/s
n2 = 500 [kg/g] [1m/cm]^2[1s/1s]^-3
=5*10^2*10^3 g*(10^2)^2 *(1s)^-3
=5*10^2*10^3*10^4 g cm^2 /s^3 =
5*10^9 g cm^2 /s^3.
hope it help.
Answered by
24
I hope it will help you !!
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